Low Pass Filters

Low-pass filters pass low frequencies and attenuate signals at frequencies higher than the cut-off frequency. The actual amount of attenuation for each frequency differs from filter to filter depending on the values of the passive components as well as the configuration of the low-pass filters.

Passive Low-Pass Filters

A passive low-pass active filter makes use of only passive components such as capacitors and inductors, The figure below shows an example of the bode plot of a passive low-pass RC filter.

Active Low-Pass Filter

An active filter uses op-amps as part of the filter network benefiting from high input and low output impedances. There are various kinds of active filters. The rest of this article demonstrate several popular filters including active low-pass, high-pass, and band-pass filters, in Butterworth, Chebyshev, and Bessel topologies.

The cut-off frequency (in Hertz) is defined as: fc =1/(2 pi R1 C) or equivalently (in
radians per second): ωc=1/(R1 X C), where f is in Hertz, R is in Ohms, and C is in Farads.

At low frequencies, where f « fc, the capacitor is open, so the gain of the amplifier is –R1/R2.
At high frequencies, where f » fc, the capacitor is a short and the gain of the circuit goes to zero.

The bode plot of the active low-pass filter is shown below.

The gain in the pass band is –R1/R2 , and the stop band drops off at -20dB/decade (or
−6 dB/octave). This is essentially a first-order filter. The closed-loop gain of the filter from the effect of the op-amp is Vout/Vin = fc = 1/2 pi R1 C)

Design Example
Design an active op-amp LPF to achieve 1.6 kHz cut-off frequency and closed-loop gain of 10.

Solution
If R1 = 10 kΩ, fp = fc = 1/(2 pi R1 C) = 1.6 kHz, C ≈ 0.01 μF
At low frequency, |Vout/Vin| = R1 / R2 = 10, hence R2 = 1 kΩ